If it's not what You are looking for type in the equation solver your own equation and let us solve it.
16x^2-15.4x=0
a = 16; b = -15.4; c = 0;
Δ = b2-4ac
Δ = -15.42-4·16·0
Δ = 237.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15.4)-\sqrt{237.16}}{2*16}=\frac{15.4-\sqrt{237.16}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15.4)+\sqrt{237.16}}{2*16}=\frac{15.4+\sqrt{237.16}}{32} $
| 0=(5x+4)(x+40) | | 4.217x-3.67=3.33-0.783x | | -4b-7b=-5b-12 | | 5x+-10=10+x | | 4+6x/8=20 | | (4^n)=64 | | 1.6=c/6 | | 5x+12=5x+18 | | 3x-4+7=180 | | 81=a/9 | | 15.25-3.8x=-26.57+2.2x | | 9/18x+7=-1/9x+2/3 | | 5x=81x | | -2y=-6y+-32 | | a-21=30 | | 3a-7=-35 | | 5x-6(3x+19=-10 | | y-7/4=3 | | 5x-6.65=3.35 | | ^2x-3+9=11 | | 74-3x=3x | | 46-x=23 | | 4=6(x-5) | | 3(5-3x)=4(2x+1) | | 15+x=3x-5 | | 8x7x=180 | | 6(x-5)=-11 | | f(6)=16807 | | 8x7x=90 | | 9x-7=13x+11 | | 3/4×(x+2/3)=-4×(x+1/4) | | 9x-7=13x+12 |